Patrick L. answered 07/04/20
We will use the 2-proportional z-test.
Ho: P1 = P2
HA: P1 ≠ P2
P1 = 64/160 = 0.40 (sample proportion for rural households who prefer a natural tree)
P2 = 89/261 = 0.341 (sample proportion for urban households who prefer a natural tree)
P-pooled = (64 + 89) / (160 + 261) = 153/421 = 0.363 (sample proportion for all households who prefer a natural tree)
z = (0.40 - 0.341) / √(0.363)(0.637)[(1/160)+(1/261)] = 0.059/0.0483 = 1.22
Look at the z-critical value for the 95% confidence level. The z-critical is 1.96.
Since 1.22 < 1.96, we fail to reject the null hypothesis. There is not sufficient evidence to show the difference in preference for natural trees vs. artificial trees between urban and rural households.