Let T=gal of 20% and S=gal 70%
T + S =100
.2T + .7S = .6*100
2T + 2S = 200
2T + 7S = 600
5S=400
S=80
T=20
James K.
asked 05/13/20A 20% solution of fertilizer is to be mixed with a 70% solution of fertilizer in order to get 100 gallons of a 60%
solution. How many gallons of the 20% solution and 70% solution should be mixed?
Let T=gal of 20% and S=gal 70%
T + S =100
.2T + .7S = .6*100
2T + 2S = 200
2T + 7S = 600
5S=400
S=80
T=20
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