J.R. S. answered 05/13/20
Ph.D. University Professor with 10+ years Tutoring Experience
4CH3NO2(l) + 7O2(g) ==> 4CO2(g) + 2N2(g) + 6H2O(g) ... balanced equation ∆Hºrxn = -1288.5 kJ
∆Hºrxn = -1288.5 kJ = ∆Hºf products - ∆Hºf reactants
You will have to look up the ∆Hºf of each reactant and product (it will be zero of N2 and O2) and multiply by the coefficients in the balanced equation and then solve for ∆Hºf of CH3NO2.
PV = nRT
(950 torr)(15.0 L) = n(62.36 Ltorr/Kmol)(373K)
n = 0.612 moles of gas
0.612 moles of gas x 0.134 = 0.082 moles N2 x 28 g/mol = 2.3 g N2