Algebra I Vertical Motion w/ Quadratic Formula

Question

Suppose you throw a rock into the air from the top of a cliff with an initial upward rate of 15 meters per second.

(a) How high will the rock be above the cliff top after 2 seconds?

(b) Where will it be after 4 seconds? (enter answers below the cliff top as negative)

(c) When will it again be at the same level you threw it?

(d) When will it hit the water, 50 meters below the cliff top?

Answer 1

Height of rock: h=-16.1*t^2+vt+s

vel

time

toss from

Drop distance: d=(t^2+t)/2*32.2