J.R. S. answered 05/12/20
Ph.D. University Professor with 10+ years Tutoring Experience
There are several ways to approach this problem. You should know the following relationships:
[H+][OH-] = 1x10-14
pH + pOH = 14
HNO3 is a strong acid so [H+] = [HNO3] = 0.0028 M
Using the above formula [H+][OH-] = 1x10-14 and solving for [OH-] we have...
2.8x10-3 x [OH-] = 1x10-14
[OH-] = 1x10-14/2.8x10-3
[OH-] = 3.6x10-12 M