Geometric sequence !!

Question

1) Find the 8th term of the geometric sequence whose common ratio is 3/2 and whose first term is 8.

2) Find the 13th term of the following geometric sequence: 4, 12, 36, 108...

Answer 1

The formula of a geometric sequence is a(n)= a1 * r ^(n-1) wehre a1 is the first term, r is the common ratio, and n is the number of the term.

For 1)

r=3/2, a1=8, n=8

so a8 = (8)*(3/2)^(8-1)

a8 = 8 * (3/2) ^ 7

For 2), the common ratio is r=3 and the first term is 4. I'll let you figure out the rest!