J.R. S. answered 05/11/20
Ph.D. University Professor with 10+ years Tutoring Experience
a). Zn(s) + 2HCl(aq) == ZnCl2(aq) + H2(g)
b). 1.21 moles Zn x 1 mol ZnCl2/mol Zn = 1.21 mole ZnCl2 produce
96.85 g HCl x 1 mol HCl/36.5 g x 1 mol ZnCl2/2 mol HCl = 1.33 mole ZnCl2 produced
Limiting reactant is Zn
c). mass ZnCl2 = 1.21 moles ZnCl2 x 136 g ZnCl2/mol ZnCl2 = 165 g ZnCl2