Need help With Chemistry

Question

What is the molarity in 850 ml of solution containing 63 grams of Sodium Hydroxide

Answer 1

Here are the steps I take to calculate the molarity:

1. Convert grams of NaOH to moles using the molar mass of NaOH, 40.0g/mol:

63g NaOH x (1 mol NaOH / 40.0g NaOH)

= 1.575 mol NaOH

2. Convert the volume of solution from mL to L.

850mL = 0.850 L

3. Molarity = (moles solute) / (L solution)

Divide the number of moles of NaOH (from step 1) by the liters of solution (step 2):

(1.575 mole NaOH) / (0.850 L)

= 1.9 M

(round to 2 sig figs because the numbers given to you in the question had 2 sig figs)