Algebra question need help please

Question

The number of bacteria in a culture is given by the function 𝑁(𝑡) = 9050𝑒^0.45t where time is measured in hours.

a. What is the relative rate of growth of this bacterium population?

b. What is the initial population of the culture?

c. How many bacteria will the culture contain in five days?

Answer 1

Here is what you need to do for each part:

a) For y = e^rt the relative growth rate is r. Compare this to the equation given, what is r?

b) Compute N(0). That is, plug in t=0 into the equation for N(t). N(0) is the iniital population. This should make sense, time is 0 at the "beginning."

c) Set t=5*24=120 (t must be expressed in hours to use your equation), and compute N(120).