239 mL of a solution of NaOH is diluted to a final volume of 1,497 mL and the new molarity is 0.185 M. Calculate the original molarity of the base. Report your answer with 4 decimal places.

Answer 1

Again, this is a simple dilution problem. Use M1V1 = M2V2

(239 ml)(x M) = (1497 ml)(0.185 M)

x = 1.1588 M