When 12.64 g of Ne occupy 1.08 L they exert pressure of 19.7 atm. Determine the temperature of neon.

Answer 1

Ideal Gas Law: PV = nRT

P = pressure = 19.7 atm

V = volume = 1.08 L

n = moles = 12.64 g Ne x 1 mol Ne/20.18 g = 0.6264 moles

R = gas constant = 0.0821 Latm/Kmol

T = temperature in Kelvin = ?

Solving for T:

T = PV/nR = (19.7 atm)(1.08 L) / (0.6264 mol)(0.0821 Latm/Kmol)

T = 414 K