What volume of water would be required to make a 0.25 M solution with 2 moles of Ba(OH)2?

Question

A. 0.625 L

B. 0.10 L

C. 1.0 L

D. 10 L

Answer 1

0.25 M = 0.25 moles Ba(OH)₂ / liter solution

2 mole/x liters = 0.25 moles/ 1 liter

x = 8 liters of solution is required.

NOTE: The question is asked incorrectly since adding 8 L of water would likely result in a final volume of solution greater than 8 L