What volume of water would be required to make a 0.25 M solution with 2 moles of Ba(OH)2?

Answer 1

0.25 M = 0.25 moles solute per liter of solution.

2 moles solute / x L = 0.25 mol/ L

x = 8 Liters of solution.

NOTE: The actual volume of water will be somewhat less than that since the 2 moles of Ba(OH)2 will occupy some volume.