J.R. S. answered 05/06/20
Ph.D. University Professor with 10+ years Tutoring Experience
2H2(g) + CO(g) <==> CH3OH(g)
Keq = [CH3OH] / [H2]2[CO] = (0.0018) / (0.12)2(0.25)
Keq = 0.50
Alex M.
asked 05/05/20The methanol is produced in a reaction chamber, in which the chemical system reaches equilibrium. some methanols removed and reactants are added to cause the equilibrium to shift to the right.
If at equilibrium, [CO(g)] = 0.25 mol/L, [H2(g)] = 0.12 mol/L, and [CH3OH(g)] = 0.0018 mol/L, the value of the equilibrium constant is;_________
Cant seem to solve this one, the help is much appreciated.
J.R. S. answered 05/06/20
Ph.D. University Professor with 10+ years Tutoring Experience
2H2(g) + CO(g) <==> CH3OH(g)
Keq = [CH3OH] / [H2]2[CO] = (0.0018) / (0.12)2(0.25)
Keq = 0.50
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