J.R. S. answered 05/06/20
Ph.D. University Professor with 10+ years Tutoring Experience
H2(g) + CO2(g) <===> H2O(g) + CO(g)
Keq = [H2O][CO]/[H2][CO2]
1.60 = (x)(x) / (0.25)(0.25)
x2 = 0.1
x = 0.32 mol/L (2 sig. figs.)
Alex M.
asked 05/05/20If the equilibrium concentrations of both H2(g) and CO2(g) are 0.25 mol/L, the final equilibrium concentration would be;______
Cant seem to figure this one out. Help much appreciated.
J.R. S. answered 05/06/20
Ph.D. University Professor with 10+ years Tutoring Experience
H2(g) + CO2(g) <===> H2O(g) + CO(g)
Keq = [H2O][CO]/[H2][CO2]
1.60 = (x)(x) / (0.25)(0.25)
x2 = 0.1
x = 0.32 mol/L (2 sig. figs.)
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