A mass of 22.5 grams of aluminum will react with how many grams of zinc chloride?

Answer 1

Single replacement (redox) reaction:

2Al(s) + 3ZnCl₂(aq) ==> 2AlCl₃(aq) + 3Zn(s) ... balanced equation

moles Al present = 22.5 g Al x 1 mol Al/26.98 g = 0.834 moles Al

moles ZnCl₂ needed to react with 0.834 mol Al:

0.834 mol Al x 3 mol Zn / 2 mol Al = 1.25 moles ZnCl₂ needed

mass ZnCl₂ needed = 1.25 mol ZnCl₂ x 136 g/mol ZnCl₂ = 170. g ZnCl₂ needed