PLEASE HELP ASAP!

Question

A container with initial volume of 1.01L is ccupied by a gas at a pressure of 1.5 atm at 25 degrees.By changing the volume , the presure of the gas increases to 6.0atm as the temperture is raised to 100 c what is the new volume ?

Answer 1

The Combined Gas Law states:

P1V1/T1 = P2V2/T2

P1 = 1.5 atm

V1 = 1.01 L

T1 = 25C + 273 = 298K (note: temperature must be in Kelvin)

P2 = 6.0 atm

V2 = ?

T2 = 100C + 273 = 373K

Solving for V2:

V2 = P1V1T2 / P2T1

V2 = (1.5 atm)(1.01 L)(373K) / (6.0 atm)(298K)

V2 = 0.316 L

Answer 2

The formula for the General Gas Equation is P1V1/T1 = P2V2/T2 i.e., PV/T is a constant

Here, we have P1 = 1.5 atm, V1 = 1.01L, and T1 = 25 C

While P2 = 6.0 atm, V2 = ???, and T2 = 100 C

Let's plug these into the Gen Gas Eqn, above: 1.5 x 1.01 / 25 = 6.0 x V2 / 100

Rearranging, we have V2 = 1.5 x 1.01 x 100 / 25 x 6 = 1.01

So, the new volume, V2 = 1.01 L