. How many grams of calcium nitrate are needed to react completely with 2.00 moles of hydrochloric acid? Ca(NO3)2 + 2HCl → CaCl2 + 2HNO3

Answer 1

Ca(NO₃)₂(aq) + 2HCl(aq) ==> CaCl₂(aq) + 2HNO₃(aq)

This reaction DOES NOT OCCUR because no precipitate, gas or liquid is formed as a product. All species are fully dissociated and soluble so there is no reaction.

However, if you want to solve the problem as an "exercise" then here goes:

Ca(NO₃)₂ + 2HCl ==> CaCl₂ + 2HNO₃

2 mol HCl x 1 mol Ca(NO₃)₂/2 mol HCl x 164 g Ca(NO₃)₂/mol = 164 g Ca(NO₃)₂ needed