A gas balloon has a volume of 106.0 liters when the temperature is 40K and the pressure is 740.0 mm of mercury. What will its volume be at 30K and 780 .0 mm of mercury pressure?

Question

Its the combined gas law

Answer 1

Combined Gas Law: P₁V₁/T₁ = P₂V₂/T₂

P₁ = initial pressure = 740.0 mm Hg

V₁ = initial volume = 106.0 L

T₁ = initial temperature = 40K

P₂ = final pressure = 780.0 mm Hg

V₂ = final volume = ?

T₂ = final temperature = 30K

Solving for V₂:

V₂ = P₁V₁T₂ / P₂T₁

V₂ = (740)(106)(30) / (780)(40)

V₂ = 75.42 L