J.R. S. answered 05/04/20
Ph.D. University Professor with 10+ years Tutoring Experience
3Ca(s) + 2H3PO4(aq) ===> Ca3(PO4)2(aq) + 3H2(g) ... balanced equation
moles of Ca = 8 g x 1 mol Ca/40 g = 0.2 moles Ca
(a) 0.2 mol Ca x 2 mol H3PO4/3 mol Ca = 0.133 mol H3PO4 reacted
60 cm3 H3PO4 * 1 L/1000 cm3 * x mol/L = 0.133 mol
x = 2.22 M = concentration of H3PO4
(b) 0.2 mol Ca x 3 mol H2/3 mol Ca = 0.2 mol H2 gas
Volume of H2 will depend on the temperature and pressure, but assuming this is at STP, the volume will be..
0.2 mol x 22.4 L/mol = 4.48 L = 4 L H2 gas (1 sig. fig.)
(c) molecules of H2 gas = 0.2 mol H2 x 6.02x1023 molecules/mol = 1.2x1023 molecules = 1x1023 molecules of H2 (1 sig. fig.)