The Dead Sea contains approximately 332.0 g of salt per kilogram of seawater. Assume this salt is all NaCl. What is the molality of this solution?

Answer 1

Molality (m) is defined as moles of solute per kg of solvent

moles of solute (NaCl) = 332 g x 1 mol NaCl/58.44 g = 5.68 moles NaCl

kg of solvent (H₂O) = 1 kg

molality = 5.68 mol/1 kg = 5.68 m