In baseball, the distance to each base is 90 ft. The distance from home to the pitcher’s mound is 60.5’, how far is it from the pitcher’s mound to 2nd base?

Question

I need to show that the distance is 66.8'(which is the answer) in two different methods and would like to have this answered by today

Answer 1

home plate to 2nd base is 60.5+n where n is the distance from the pitcher's mound to 2nd base

home to first and first to second form a right triangle

the hypotenuse is home plate to 2nd base

use the Pythagorean Theorem

(60.5+n)^2=90^2+90^2

3660.25+121n+n^2=8100+8100

n^2+121n+3660.25-16,200=0

n^2+121n-12539.75=0

us the quadratic formula

(-121±√(14641+50159)/2

(-121±√64800)/2

(-121+254.55844)/2

133.55844/2

66.779≈66.8 feet