
Mark M. answered 05/02/20
Mathematics Teacher - NCLB Highly Qualified
z3 = ||z||3 (cos θ + i sin θ)3
z3 = 64 (cos 2π/3 + i sin 2π/3)3
z3 = 64 (cos 2π + i sin 2π)
z3 = 64 (1 + 0)
z3 = 64
Nahum S.
asked 05/02/20(-2+2i√3)3 ????????????????????????????????????????????????????????????????
Mark M. answered 05/02/20
Mathematics Teacher - NCLB Highly Qualified
z3 = ||z||3 (cos θ + i sin θ)3
z3 = 64 (cos 2π/3 + i sin 2π/3)3
z3 = 64 (cos 2π + i sin 2π)
z3 = 64 (1 + 0)
z3 = 64
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.