J.R. S. answered • 05/02/20
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It seems obvious that you left something out of the question, as eluded to by the previous answer. Let us assume that you have reacted the Zn with HCl as follows:
Zn(s) + 2HCl(aq) ==> ZnCl2(aq) + H2(g)
Using dimensional analysis and the information provided, and assuming HCl is in excess, we have...
55.0 g Zn x 1 mol Zn/65.4 g x 1 mol ZnCl2/mol Zn = 0.841 mol ZnCl2 formed (to 3 significant figures)
Marvin F.
You need to learn to use dimensional analysis. Would you like me to teach you this?
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05/02/20
J.R. S.
tutor
Yes. You divide the mass of Zn by the molar mass as shown in the answer. Like @Marvin F says, you really need to learn how to use dimensional analysis. Note how g x mol/g cancels the g units and you end up with moles.
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05/02/20
Logan P.
Do you divide 55.0 g Zn by the molar mass of Zn?05/02/20