Reaction 1 and Reaction 2 are the first and second step in series for overall reaction 3.

Question

1) CaCO_{3 (s)} <--> Ca²⁺ _(aq) + CO₃^2-_(aq) K_C1 = 10^-6.3

2) H⁺_(aq) + CO₃^2-_(aq) <--> HCO₃^-_(aq) K_C2 = 10^-10.3

3) ? <--> ? K_total = ?

A. Write the reaction for 3. Show work and canceling of species

B. What is the value of K_Total ? Show work

Answer 1

Hey Kierstin,

The answer to A is CaCO₃(s) + H⁺(aq) <--> Ca₂⁺(aq) + HCO₃^-(aq). You'll get this if you stack 1) and 2) on top of each other and cross out CO₃^2-(aq) on both sides.

The answer to B is 2.51 x 10^-17. You'll get this if you multiply K_C1 and K_C2 together. Multiplying the equilibrium constants of previous reactions gives you the equilibrium constant for the overall reaction.

If you have any more questions let me know or book a session online.

Best,

Christopher