Please help me out with math, thank you

Question

f(x) and g(x) are a differentiable function for all reals and h(x) = g[f(3x)]. The table below gives selected values for f(x), g(x), f '(x), and g '(x). Find the value of h '(1)

x	1	2	3	4	5	6
f(x)	0	3	2	1	2	0
g(x)	1	3	2	6	5	0
f '(x)	3	2	1	4	0	2
g '(x)	1	5	4	3	2	0

Answer 1

By the chain rule, we have:

h'(x) = 3f'(3x)g'[f(3x)]

Therefore,

h'(1) = 3f'(3)g'(f(3)) = 3(1)g'(2) = 3(1)(3) = 9