J.R. S. answered 05/02/20
Ph.D. University Professor with 10+ years Tutoring Experience
1). q = mC∆T
q = heat energy = 103 J
m = mass = 10.6 g
C = specific heat of titanium (look it up in a table)
∆T = change in temperature = ?
Solve for ∆T and add that to 21.1º to get the final temperature
2). q = mC∆T
all variable are as described in #1
Solve for ∆T and subtract it from 39.0º to get the initial temperature