Calculate the value of the equilibrium constant ( K) for the following balanced redox reaction at 25°C. Pb 2+(aq) + Cu(s) → Pb(s) + Cu 2+(aq) E° = -0.47 V

Answer 1

Pb2+(aq) + Cu(s) ==> Pb(s) + Cu2+(aq)

Eº = -0.47 This is not spontaneous and will not proceed as written

Eº = 00592/n log K @25ºC and 1 atm

-0.47 = 0.0592/2 (log K)

-0.47 = 0.0296 log K

log K = -15.88

K = 1.3x10^-16 (essentially doesn't happen)