35.0 mL of 0.15 M H2SO4 are titrated with 24.85 mL of KOH. a. Write a balanced equation for this titration. b. Determine molarity of KOH.

Question

35.0 mL of 0.15 M H2SO4 are titrated with 24.85 mL of KOH.  a. Write a balanced equation for this titration. b. Determine molarity of KOH.

J.R. S. · Accepted Answer

H2SO4 + 2KOH ==> 2H2O + K2SO4 ... balanced equation

moles H2SO4 present = 35.0 ml x 1 L/1000 ml x 0.15 mol/L = 0.00525 moles H2SO4

moles KOH needed to neutralize 0.00525 mol H2SO4 = 2 x 0.00525 = 0.0105 moles KOH

molarity KOH = moles / liter = 0.0105 mol/0.02485 L = 0.42 M (to 2 sig. figs.)

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