J.R. S. answered 04/30/20
Ph.D. University Professor with 10+ years Tutoring Experience
Using ∆Gº = - RT ln Kc and substituting values of R = 0.008314 kJ/Kmol and T = 298K, we obtain...
17.5 kJ = -(0.008314)(298) ln Kc
17.5 = -2.48 ln Kc
-ln Kc = 7.06
Kc = 8.6x10-4