What is the probability of P(AUB), if P(A)=0.23, P(B)=0.41, and P(AnB)=0.12? Express the result as a decimal rounded to the nearest hundredth.

Question

Express Result as a decimal to the nearest hundredth

Answer 1

P(A or B) = P(A) + P(B) - P)A and B) = 0.23 + 0.41 - 0.12 = 0.52