Find the standard form of the equation of the parabola with the given characteristics. Focus: (0, 0); Directrix: y = 10

Answer 1

The focus is (0,0) and the directrix is y=10. The vertex is equidistant from both: (0,5)

To go from the vertex to the focus we go down 5, p= -5

The equation in conic section form is

X^2 = (4)(-5) (y - 5)

To get standard form we solve for y

y = -1/20 x^2 + 5