two forces of 692 newtons and 423 newtons act at a point. The resultant force is 786 newons. Finde the angles between the forces

Question

John M. · Accepted Answer

I let 692N act horizontally and 423N act at an angle θ to the horizontal.The equation would be 692N + 423CosΘ = 786423CosΘ = 94CosΘ = 0.222222Θ = 77.160°

two forces of 692 newtons and 423 newtons act at a point. The resultant force is 786 newons. Finde the angles between the forces

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two forces of 692 newtons and 423 newtons act at a point. The resultant force is 786 newons. Finde the angles between the forces

1 Expert Answer

Still looking for help? Get the right answer, fast.

OR

RELATED TOPICS

RELATED QUESTIONS

tan^2x-sin^2x=tan^2xsin^2x

I need help trying to sole tan^2 x =1 where x is more than or equal to 0 but x is less than or equal to pi

find all solutions to the equation in (0, 2pi) sin(6x)+sin(2x)=0

(2sin18)(cos18)

how do i go about solving a trig identity; that simplify s 1-sin^2 theta/1-cos theta

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