J.R. S. answered 04/29/20
Ph.D. University Professor with 10+ years Tutoring Experience
q = heat energy = mC∆T
m = mass = 54.1 g
C = specific heat = 4.18 J/g/degree
∆T = change in temperature =100º - 33º = 67º
q = (54.1 g)(4.18 J/g/degree)(67 degrees)
q = 15,151 J = 15.2 kJ