If 0.10 moles of argon gas exert a pressure of 0.84 atm at 25°C what volume does it occupy in L?

Answer 1

Ideal Gas Law:

PV = nRT

P = pressure =0.84 atm

V = volume = ?

n = moles = 0.10

R = gas constant = 0.0821 Latm/Kmol

T = temperature in Kelvin = 25ºC + 273 = 298K

Solving for V:

V = nRT/P = (0.1)(0.0821)(298) / 0.84

V = 2.9 liters (2 sig.figs.)