Propane (C3H8) reacts with excess oxygen gas to produce carbon dioxide and water. If you start with 19.3 g of propane, how many grams of carbon dioxide is produced?

Answer 1

C₃H₈ + 5O₂ ==> 3CO₂ + 4H₂O ... balanced equation

The reaction type is COMBUSTION

The limiting reactant has to be propane since it tells you that oxygen is in excess

Use the stoichiometry of the balanced equation along with dimensional analysis to find the answer:

19.3 g C₃H₈ x 1 mol C₃H₈/44.1 g x 3 mol CO₂/mol C₃H₈ x 44 g CO₂/mol CO₂ = 57.8 g CO₂ (3 sig.figs.)