J.R. S. answered 04/27/20
Ph.D. University Professor with 10+ years Tutoring Experience
Looking up the standard reduction potential for Ni2+ + 2e- ===> Ni(s), I find it to be -0.23 V
Standard reduction potential for 2H+ + 2e- ===> H2(g) is 0 V
Thus, H+ will be reduced (cathode) and Ni(s) will be oxidized (anode)
Eºcell = cathode - anode = 0 - (-.023)
Eºcell = +0.23 V