Tom K. answered 04/25/20
Knowledgeable and Friendly Math and Statistics Tutor
Since the statement says not, this is a 2-sided test. Thus, as 4.6 > 3.1, we can find the chi-squared cutoff using a cumulative probability of .975 or a right tail of .025
As n = 20, we have 19 df
From Excel, chisq.inv.rt(.025,19) = 32.8523268617297
(n-1)s2/σ2 = 19 * 4.62/3.12 =
As 41.8355879292404 > 32.8523268617297, we reject the null hypothesis that the standard deviation is 3.1