J.R. S. answered 04/26/20
Ph.D. University Professor with 10+ years Tutoring Experience
6HCl + 2Al ==> 2AlCl3 + 3H2 ... balanced equation
Use dimensional analysis and stoichiometry:
10.0 g Al x 1 mol Al/26.98 g x 3 mol H2/2 mol Al x 2 g H2/mol H2 = 1.11 g H2 (3 sig. figs.0