
Yefim S. answered 04/25/20
Tutor
5
(20)
Math Tutor with Experience
Area of n-gon An = 1/2R2nsin(360°/n); A20 = 1/2·102·20sin(360°/20) = 1000sin(18)° ≈ 309 mm2
Audrey A.
asked 04/25/20Yefim S. answered 04/25/20
Math Tutor with Experience
Area of n-gon An = 1/2R2nsin(360°/n); A20 = 1/2·102·20sin(360°/20) = 1000sin(18)° ≈ 309 mm2
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