thank you so much for the help:)

Question

   Consider the following reversible reaction: COCl₂(g) ⇌ CO(g) + Cl₂(g)   

            What is the equilibrium concentration of Cl₂ if the initial concentration of

            COCl₂ = 0.250 M and Kc = 8.33 × 10^-4.

Answer 1

COCl₂(g) ⇌ CO(g) + Cl₂(g)   

Kc = [CO][Cl₂]/[COCl₂] = 8.33x10^-4

8.33x10^-4 = (x)(x)/0.250 - x

x² + 8.33x10^-4x - 2.08x10^-4 = 0

x = 0.0140 M

Equilibrium concentration of Cl₂ = 0.0140 M