13. For the following reaction, Kc = 1.0 × 1012 at 500 K. 2 SO2(g) + O2(g) ⇌ 2 SO3(g). What is the value of Kp for this reaction at the same temperature?

Answer 1

Kp = Kc(RT)^∆n

where ∆n is the change in the number of moles of gas = -1 since 3 moles on reactant side and 2 on product

Kc = 1.0x10¹²

R = gas constant = 0.0821 Latm/Kmol

T = temp in Kelvin = 500K

Kp = 1.0x10¹² (0.0821 x 500)^-1

Kp = 2.4x10¹⁰