J.R. S. answered 04/24/20
Ph.D. University Professor with 10+ years Tutoring Experience
For a second order reaction, t1/2 = 1/k[A]o
We know [A]o = 0.55 M and t1/2 = 10.5 s, therefore from t1/2 = 1/k[A]o we can solve for k
10.5 s = 1/0.55 M x k
k = 1/(0.55 M)(10.5 s)
k = 0.173 M-1s-1