0.690 mol sample of oxygen gas at a temperature of 24.0 C is found to occupy a volume of 26.7 liters. What is the pressure of this gas sample in mm hg?

Answer 1

Ideal Gas Law:

Note: since pressure is to be in mm Hg, we can use R = 62.36-mm Hg/Kmole, and also temperature must be in degrees Kelvin.

PV = nRT and solving for P (pressure)...

P = nRT/V = (0.690 moles)(62.35 L-mm Hg/Kmol)(297K) / 26.7 L

P = 479 mm Hg