J.R. S. answered 04/23/20
Ph.D. University Professor with 10+ years Tutoring Experience
Write a balanced equation for the reaction:
NaHCO3 + CH3COOH ==> CH3COONa + H2CO3 ==> CO2 + H2O + CH3COONa
Theoretical yield of CH3COONa:
5.40 g NaHCO3 x 1 mol NaHCO3/84.0 g x 1 mol CH3COONa/mol NaHCO3 x 82.0 g/mol = 5.27 g
Percent yield:
actual yield/theoretical yield (x100%) = 4.80 g/5.27 g (x100%) = 91.1% yield