Gas Law Chemistry

Question

What is the volume of 0.0800 g of C2H2F4 vapor at 0.971 atm and 38.7◦C?

Answer 1

Assuming C2H2F4 behaves as an ideal gas, and using the ideal gas law PV = nRT, we have...

V = nRT/P

n = moles = 0.0800 g C2H2F4 x 1 mol/102 g = 7.84x10^-4 moles

R = gas constant = 0.0821 Latm/Kmol

T = temperature in K = 38.7 + 273.15 = 311.9K

P = pressure = 0.971 atm

V = volume = ?

V = (7.84x10^-4 moles)(0.0821 Latm/Kmol)(311.9) / 0.971

V = 0.0207 L = 20.7 mls