Find all possible values of x. Of a trapezoid with its midsegment

Question

8-x

4x (midsection)

X^2 + 10

Answer 1

The length of the midsection is equal to one-half of the sum of the lengths of the two bases.

4x = (8 - x)(x² + 10) / 2

8x = -x³ + 8x² - 10x + 80

0 = -x³ + 8x² - 18x + 80

The one real solution is irrational at x ≈ 7.0558.