In triangle ABC, find side a when side b=4 and side C=8

Answer 1

In order to get this imfo; at least 1 angle or another side is needed.

Answer 2

Assuming this is a right triangle, we can use the Pythagorean Theorem a²+b² = c². Plug in b=4 and c=8 into the equation, and you get a²+4² = 8².. Simplifying, we get a²+16 = 64. Subtracting 16 from both sides, we get a² = 48. Take the square root of both sides, and the answer is a= the square root of 48, which is about 6.93 if you round.

Answer 3

Demi-

If this is a right triangle then you can solve for side A using Pythagorean Theorem: A^2 + B^2 = C^2

Since B = 4 and C = 8, we can populate the formula like this:

A^2 + (4)^2 = (8)^2

so A^2 +16 = 64 subtract 16 from both sides

A^2 = 48 then take the square root of both sides

A = the square root of 48, or 4sq.rt.2