What pressure (in kPa) would be exerted by 0.86 mol of a gas in a 12.2 L container at 22C?

Answer 1

Use the ideal gas law to solve for pressure:

PV = nRT

P = ?

V = 12.2 L

n = 0.86 mol

R = 8.314 LkPa/Kmol

T = 22C + 273 = 295K

Solving for P:

P = nRT/V = (0.86)(8.314)(295)/12.2

P = 173 kPa