J.R. S. answered 04/21/20
Ph.D. University Professor with 10+ years Tutoring Experience
V1M1 = V2M2
(2.00 ml)(0.0295 M) = (10.0 ml)(x M)
x = 0.00590 M (to 3 significant figures)
Rafael V.
asked 04/21/20If 2.00 mL of 0.0295 M CuSO4 is diluted to 10.0 mL with pure water, what is the molar concentration of copper(II) sulfate in the diluted solution?
Molar concentration =_____ M
J.R. S. answered 04/21/20
Ph.D. University Professor with 10+ years Tutoring Experience
V1M1 = V2M2
(2.00 ml)(0.0295 M) = (10.0 ml)(x M)
x = 0.00590 M (to 3 significant figures)
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